Diketahui fx=ax+b. F(4)= -3 dab f(-2)=9 nilai f(6) adalah

f(x)= ax + b
f(4)= 4a + b = -3
f(-2)=-2a + b = 9
----------------------- -
6a=-12
a = -2

4(-2) + b=-3
-8+b=-3
b=-3 + 8
b=5

f(6)= 6a + b
=6(-2) + 5
=-12 + 5 = -7

f(x) =a(x) +b
f(4)=a.4+b=-3
=4a+b=-3..........(1)
f(-2)=ax+b=9
= a.(-2)+b=9
=-2a+b=9.........(2)
f(6)=a. 6+b=0
=6a+b=0