[tex] \\ 1 \: \: \frac{lim}{x - > - 2} \: \: \frac{ {x}^{3} \: + 9 }{ {x}^{4} - 16 \: } \\ \\ 2 \: \: \frac{lim \: }{x -> 2} \: \: \frac{ {x }^{2}

jawab


1)
limit (x -> -2)  (x³ +9)/(x⁴ -16) =
substitusi x = - 2
= ((-2)³ +9 )/(-2)⁴ -16))
=  (-8 +9) / (16 - 16)
= 1/0
= ∞

2)
limit (x -> 2) (x² -3x + 2)/(x² -4) 
limit (x -> 2) (x -2)(x -1)/ (x -2)(x +2)
limit (x -> 2 ) (x-1)/(x +2)
x= 2
= (2 -1)/(2 +2)
= 1/4