Bantu saya ngerjain ini dong, ini sama caranya ya

[tex]14. \: \cos(x) = \frac{12}{13} . \: dimana \: x \: lancip. \: nilai \:sin( 2x )= .... \\ sin(2x) = 2sinxcosx = 2 \times \frac{5}{13} \times \frac{12}{13} = \frac{120}{169} \\ 15. \: {sin}^{2} a = \frac{9}{25} \\ \: {cos}^{2} a = 1 - {sin}^{2} a = 1 - \frac{9}{25} = \frac{16}{25} \\ [/tex]