Luas bangun diatas adalah ....cm persegi tolong dijawab pakai caranya

Please, let me answer your question :)
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Mapel : Matematika
Tentang : Bangun Datar
Pembahasan :

Diketahui :

Persegi Panjang :
- p = 20 cm
- l = 12 cm

Trapesium :
- a = 20 cm
- b = 32 cm
- t = 22 - 12 = 10 cm

Ditanya :
- L Gabungan

LPP= p x l
LPP= 20 x 12
LPP= 240 cm²

LT= ½ x (a+b) x t
LT= ½ x (20+32) x 10
LT= ½ x 52 x 10
LT= 26 x 10
LT= 260 cm²

L Gabungan : 240 + 260
L Gabungan : 500 cm²

Yg D jawabannya

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diketahui bangun 2 persegi panjang dan segitiga
L persegi panjang(1) = p × l = 12 × 20 = 240
L persegi panjang(2) = p × l = 10 × 20 = 200
L segitiga = 1/2 a × t = 1/2 × 12 × 10 = 6 × 10 = 60

luas bangun tersebut = 240+200+60 = 500