9 L+500cm3 = .......dm3 2 L+4 dL=........cm3 4L+ 48cm3=........cc

== Jawaban ==
1.
=> 9 L + 500 cm³ = ... dm³
=> 9 dm³ + ( 500 / 1000 ) dm³ = ... dm³
=> 9 dm³ + 1/2 dm³ = ... dm³
=> 9,5 dm³
atau
[tex]9 \ \frac{1}{2} {dm}^{3} [/tex]

2.
=> 2 L + 4 dL = ... cm³
=> 2 L + 4 dL = ... mL
=> 2000 mL + 400 mL = ... mL
=> 2400 mL

3.
=> 4 L + 48 cm³ = ... cc
=> 4 L + 48 cm³ = ... mL
=> 4 L + 48 mL = ... mL
=> 4000 mL + 48 mL = ... mL
=> 4048 mL

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