Matematika

Pertanyaan

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    KA = B

    [tex] \left[\begin{array}{ccc}k&l\\m&n\end{array}\right] \left[\begin{array}{ccc}2\\0\end{array}\right] \,= \left[\begin{array}{ccc}8\\-2\end{array}\right] [/tex]


    2k = 8 -->k = 4
    2m  - 2 --> m = -1

    KC = D

    [tex]\left[\begin{array}{ccc}k&l\\m&n\end{array}\right] \left[\begin{array}{ccc}1\\1\end{array}\right] \,= \left[\begin{array}{ccc}6\\-2\end{array}\right] [/tex]

    4  +l  = 6 --> l = 2
    -1+n = 2 --> n = 3

    k= 4
    m= -1
    l = 2
    n = 3

    [tex] \left[\begin{array}{ccc}4&2\\-1&3\end{array}\right] \left[\begin{array}{ccc}-2\\1\end{array}\right] \,= \left[\begin{array}{ccc}-6\\5\end{array}\right] [/tex]

    K (-2,1) =  (-8+2), (2+3) = (-6. 5)