Ada yang bisa bantu ?

jawab

a)
= 1/3 x³- 1/2 x²]²₀
= 1/3(8) - 1/2 (4)
= 8/3 - 2
= 2/3

b)
= 1/2 sin (2t - x)]ˣ ₀
= 1/2 [ sin (2x- x) - sin (0- x)]
= 1/2 ( sin x - sin (-x))
=  1/2 (sin x + sin x)
= sin x

c)
u= 3x + 4
du = 3dx
dx = 1/3 du

u = 3x + 4
x = 2 --> u = 10
x= 0 --> u = 4

²₀∫(3x+4)^(1/2) dx =

= ₄¹⁰∫ 1/3 u^(1/2) du

= [ 1/3 . 2/3 u^(3/2)]¹⁰₄

= 2/9 ( u √ u ]¹⁰₄

= 2/9 ( 10 √10 - 4√4)

=2/9 (10√10 - 8)