mohon di bantu y....
Matematika
BaraBuana
Pertanyaan
mohon di bantu y....
1 Jawaban
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1. Jawaban MisykahGolar
a = 1/9
b = 16
c = 125
2a^-1/2 - b^1/4 + c^1/3 =
(2 x (1/9)^-1/2) - 16^1/4 + 125^1/3 =
(2 x (3^-2)^-1/2) - (2^4)^1/4 + (5^3)^1/3 =
(2 x 3^1) - 2^1 + 5^1 =
6 - 2 + 5 =
9
semoga membantu:)