Gambarlah garis dengan persamaan berikut : a. y - 3x = 12 b. y = - 6x + 5 c. 2y + 3 = 8x d. 5x + 3y = 15 e. 7 + 2x - 6y = 0 f. 11y - 3 = 5x Tolong dijawab secep

Berapa titik? Kalo 2 titik monggo dilihat :D
a. y - 3x = 12
jika x = 0
maka = y - 3.0 = 12
y=12 => (0,12)

jika y=3
maka 3 - 3x = 12
3x = 12-3
3x= 9
x=3 (3, 3)

b. y = - 6x + 5
jika x = 1
maka = y = -6.1 + 5
y= -6 + 5 = -1 (1, -1)

jika x = 0
maka = y = -6.0 + 5
y = 5 (0, 5)

c. 2y + 3 = 8x
jika y = [tex] \frac{5}{2} [/tex]
maka = 2.[tex] \frac{5}{2} [/tex] + 3 = 8x
5 + 3 = 8x
8 = 8x
-8x = -8 x= 1 (1, [tex] \frac{5}{2} [/tex])

jika x=3
maka= 2y + 3 = 8.3
2y = 24-3
y = [tex] \frac{21}{2} [/tex] (3, [tex] \frac{21}{2} [/tex])

d. 5x + 3y = 15
jika x = 6
maka = 5.6 + 3y = 15
30 + 3y = 15
3y = 15 - 30
3y = -15
y = -5 (6, -5)

jika y = 10
maka = 5x + 3.10 = 15
5x = 15-30
5x=-15
x= -3 (-3, 10)

e. 7 + 2x - 6y = 0
jika x= 14
maka 7 + 2.14 - 6y = 0
7 + 28 - 6y = 0
35 - 6y = 0
-6y = -35
y = [tex] \frac{35}{6} [/tex] (14,[tex] \frac{35}{6} [/tex])

jka x = 1
maka = 7 + 2 -6y = 0
9 - 6y = 0
-6y = -9
y = [tex] \frac{9}{6} [/tex] = [tex] \frac{3}{2} [/tex] (1, [tex] \frac{3}{2} [/tex])

f. 11y - 3 = 5x
jika x = 6
maka = 11y -3 = 5.6
11y - 3 = 30
11y = 30 + 3
11y = 33
y = 3 (6, 3)

jika y = 13
maka = 11.13 - 3 = 5x
143 - 3 = 5x
140 = 5x
-5x = -140
x = 28 (28, 13)