tolong tulis jawaban nya pakai rumus abc

jawab

x₁₂= - b +- √(b²- 4ac) / 2a

1) x² +12x -13=0
a = 1, b = 12 , c = -13
x₁₂ =  -12 +- √(144 + 52)  /(2)
x₁₂ = -12 +_ 14/(2)
x1 = (-12 + 14)/2 = 1
x2 = (-12 -14)/2 = -13

2) x² - 4x - 2 = 0
a= 1, b = - 4, c = -2
x₁₂ = 4 +- √(16 +8) /(2)
x₁₂ = 4+_2√6 /(2)
x₁ = (4 + 2√6)/2 = 2 + √6
x₂ = (4 - 2√6) /2 = 2 - √6