Diketahui f(x)=x-5 g(x)=x2-3 (2 itu pangkat jadi x pangkat 2 dan h(x)=2x. Tentukan: a.(f dot )(2) b.(f dot g(dot h)(-1)

[tex]f = x - 5 \\ g = {x}^{2} - 3 \\ h = 2x[/tex]

a. (fog)(2)
(fog)(x)=(x^2-3)-5
(fog)(x)=x^2-8
(fog)(2)=2^2-8
(fog)(2)=4-8
(fog)(2)= -4

b. (fogoh)(-1)
[tex](fogoh)(x) = ({(2x)}^{2} - 3) - 5 \\ (fogoh)(x) = (4 {x}^{2} - 3) - 5 \\(fogoh)(x) = 4 {x}^{2} - 8 \\ \\ (fogoh)(-1) = 4 { (- 1)}^{2} - 8 \\ (fogoh)(-1) = 4 - 8 \\ (fogoh)(-1) = - 4[/tex]

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