SBMPTN

Pertanyaan

jika p=6 dan q=4 serta r=(p+3q)/pq, berapakah nilai (p+q)/r?

2 Jawaban

  • p = 6 dan q = 4
    r = (p + 3q)/pq
    r = (6 + 3.4)/6.4
    r = (6 +12)/24
    r = 18/24 = 3/4
    (p +q)/r = (6+4)/(3/4)
    10/(3/4)
    = 10 × 4/3
    = 40/3
    = 13 1/3
  • r= (p+3q)/pq          nilai (p+q)/r ?
      = ( 6 + 3.4)/6.4          = (6+4)/3/8
      = 18/24 = 3/8            = 10 / 3/8
                                       = 10 x 8/3 = 80/3 = 26 2/3 

Pertanyaan Lainnya