• jawab

    ΔKLM siku siku di  L
    KM= 12 cm
    KL = 8 cm
    KM² = KL² + ML²
    ML² = KM² - KL²
    ML² = 12² -8² = 80
    ML = √80 = 4√5

    <M = θ
    tan θ = tan (<M) = KL/ML = 8/4√5 = 2/√5 = (2/5) √5

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