sebuah belah ketupat panjang diagonalnya masing-masing 12 cm dan 16 cm tentukan kelilingnya

d1 = 12 cm, d2 = 16 cm
1/2d1 = 12/2 = 6 cm
1/2d2 = 16/2 = 8 cm

s = √(1/2d1² + 1/2d2²)
s = √(6² + 8²)
s = √(36 + 64)
s = √100 = 10 cm

K = 4 x s
K = 4 x 10
K = 40 cm

Mapel : Matematika
Bab : Bangun datar

d1 = 12 cm
1/2d1 = 1/2(12) = 6 cm

d2 = 16 cm
1/2(d2) = 1/2(16) = 8 cm

Sisi Miring = Akar 6^2 + 8^2
Sisi Miring = Akar 36 + 64
Sisi Miring = Akar 100 = 10 cm

K = 4s
K = 4(10)
K = 40 cm