nilai y dari spldv 2×+3y = 4 dan ×-y=3 adalah a.y=1 b.y=2 c.y=3 d.y=4

Metode Eliminasi
2x + 3y = 4 x 1 = 2x + 3y = 4
x - y = 3 x 3. = 3x - 3y = 9
_________-
-1x. = -5
x. = -5/-1
x. = 5
Metode Substitusi
2x + 3y = 4
2.5 + 3y = 4
10 + 3y = 4
3y = 10-4
3y = 6
y = 6/3
y = 2

semoga membantu:)