Soal tentang invers matriks

Jawabannya e. Itu rumusnya

A = [tex] \left[\begin{array}{cc}2&8\\1&3\end{array}\right] [/tex]
[tex] A^{-1} = \frac{1}{2(3) - 8(1)} \left[\begin{array}{cc}3&-8\\-1&2\end{array}\right] = -\frac{1}{2} \left[\begin{array}{cc}3&-8\\-1&2\end{array}\right] (E)[/tex]