Matematika

Pertanyaan

1.sederhanakanlah bentuk akar berikut dengan menggunakan sifat [tex] \sqrt{axb} = \sqrt{a} x \sqrt{b}[/tex]
a.[tex] \sqrt{27} [/tex]
b.[tex] \sqrt{125} [/tex]
c.[tex] \sqrt{288} [/tex]
d.[tex] \sqrt{180} [/tex]
e.[tex] \sqrt{175} [/tex]
f.[tex] \sqrt{192} [/tex]
g.[tex] \sqrt{363} [/tex]
h.[tex] \sqrt{243} [/tex]
i.[tex] \sqrt{450} [/tex]
j.[tex] \sqrt{507} [/tex]

1 Jawaban

  • [tex]a.\ \sqrt{27} = \sqrt{9 \times 3} = \sqrt{9} \times \sqrt{3} = 3 \sqrt{3} \\ \\ b.\ \sqrt{125}= \sqrt{25 \times 5} = \sqrt{25} \times \sqrt{5} = 5 \sqrt{5} \\ \\ c.\ \sqrt{288}= \sqrt{144 \times 2} = \sqrt{144} \times \sqrt{2} = 12 \sqrt{2} \\ \\ d.\ \sqrt{180}= \sqrt{36 \times 5} = \sqrt{36} \times \sqrt{5} = 6 \sqrt{5} \\ \\ e.\ \sqrt{175}= \sqrt{25 \times 7} = \sqrt{25} \times \sqrt{7} = 5 \sqrt{7} \\ \\ f.\ \sqrt{192}= \sqrt{64 \times 3} = \sqrt{64} \times \sqrt{3} = 8 \sqrt{3} [/tex]

    [tex]g.\ \sqrt{363}= \sqrt{121 \times 3} = \sqrt{121} \times \sqrt{3} = 11 \sqrt{3} \\ \\ h.\ \sqrt{243}= \sqrt{81 \times 3} = \sqrt{81} \times \sqrt{3} = 9 \sqrt{3} \\ \\ i.\ \sqrt{450}= \sqrt{225 \times 2} = \sqrt{225} \times \sqrt{2} = 15 \sqrt{2} \\ \\ j.\ \sqrt{507}= \sqrt{169 \times 3} = \sqrt{169} \times \sqrt{3} = 13 \sqrt{3}[/tex]

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