mohon bantuannya, lupa cara ngerjainnya hehe

Kelas 10 Matematika
Bab Akar dan Pangkat

10/(√6 + 3√2)
= (10/(3√2 + √6)) . (3√2 - √6)/(3 √2 - 6)
= (30√2 - 10√6)/(9 . 2 - 6)
= (30 √2 - 10 √6)/12
= (10/12) . (3√2 - √6)
= (5/6) . (3√2 - √6)

[tex] \frac{10}{( \sqrt{6 } ) + 3 \sqrt{2} } = \frac{10}{( \sqrt{6 } ) + 3 \sqrt{2} } \times \frac{ \sqrt{6} - 3 \sqrt{2} }{ \sqrt{6 - 3 \sqrt{2} } } \\ \frac{10 \sqrt{6} - 30 \sqrt{2} }{6 - (9.2)} \\ \frac{10 \sqrt{6} - 30 \sqrt{2} }{ - 12} \\ \frac{5 \sqrt{6} }{ - 6} + \frac{15 \sqrt{2} }{6} \\ - \frac{ 5 \sqrt{6} }{6} + \frac{5 \sqrt{2} }{2} \\ \frac{5 \sqrt{2} }{2} - \frac{5 \sqrt{6} }{6} [/tex]
Jadi jawabannya C