Peladen No 19 dan 20. Hari Senin di kumpulin.

jawab

19. 
r alas tabung = 10
r bola = 6cm

tinggi air naik = Vbola/ luas alas tabung
t = 4/3 .π 6³/ ( π 10²)
t = 288/100
t = 2,88 cm


20.
kerucut besar  
r1 = 20  
r2 = 10

19.

Rt = 10 cm
Rb = 6 cm

tinggi air naik = 4/3.π.6^3 / π 10^2
tinggi air naik = 4/3.6^3/10^2
tinggi air naik = 288/100 = 2,88 cm

20.

x/10 = (x+26)/20
20x = 10x + 26.10
20x = 10x + 260
10x = 260
x = 26 -> s = 2.26 = 52
T2 = 52^2 - 20^2 = 2.304
t = 48cm t1 = 1/2.48 = 24 cm
V = 1/3 π (20^2 .48-10^2.24)
V = 1/3 π ( 400.48-100.24)
V = 1/3 π ( 19.200-2.400 )
V = 1/3 × 16.800 π = 5.600 π
V = 17.600 cm3 = 17,6 l