guys aku gak tau caranya, berjam2 aku coba gabisa, bantu jawab dong, pleaseeeee

[tex] \frac{ \sqrt{2} }{ \sqrt{2 + \sqrt{4x} } } = ... \\ \\ = \frac{ \sqrt{2} . \sqrt{2 - \sqrt{4x} } }{2 - \sqrt{4x} } \\ \\ = \frac{ \sqrt{2} . \sqrt{2 - \sqrt{4x} }( 2 + \sqrt{4x})}{4 + 4x} \\ \\ lim_{x = 0} \frac{ \sqrt{2}. \sqrt{2 - \sqrt{4x} } (2 + \sqrt{4x})}{4 + 4x} = \\ \\ = \frac{ \sqrt{2}. \sqrt{2 - \sqrt{4(0)} }(2 + \sqrt{4(0)}) }{4 + 4(0) } \\ \\ = \frac{ \sqrt{2} \times \sqrt{2} \times 2 }{4} \\ \\ = 1[/tex]