²log24+³log12-²log3+³log¼=? Tolong dibantu ya...

²log24 + ³log12 - ²log3 + ³log¼
= (²log24 - ²log3) + (³log12 + ³log¼)
= ²log(24/3) + ³log(12×¼)
= ²log8 + ³log3
= 3 + 1
= 4