persamaan garis melalui titik (2,-3) dan ( -4,7)

y - y1 • x - x1
------- = -----
y2 - y1 • x2 - x1

y - (-3) • x - 2
--------- = ------
7 - (-3) • -4 - 2

y + 3 • x - 2
------- = ------
10 •••• -6

-6 (y+3) = 10 (x-2)
-6y - 18 = 10x - 20
-10x - 6y = -2
---------------------- :2
-5x - 3y = -1

Gradien dan Garis Lurus

x1 = 2
y1 = -3
x2 = -4
y2 = 7

Persamaan garisnya,

⇒ [tex] \frac{y - y1}{y2 - y1} = \frac{x - x1}{x2 - x1} [/tex]
⇒ [tex] \frac{y + 3}{10} = \frac{x - 2}{-6} [/tex]   |Cross Product|
⇒                  10 (x - 2) = -6 (y + 3)
⇒                    10x - 20 = -6y - 18
⇒     10x + 6y -20 + 18 = 0
⇒              10x + 6y - 2 = 0  |:2|
⇒                5x + 3y - 1 = 0


Semoga Membantu!!!