Mau nanya dong ini soal caranya gimana yah?
Matematika
Yanuar9925
Pertanyaan
Mau nanya dong ini soal cara"nya gimana yah?
1 Jawaban
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1. Jawaban Anonyme
jawab
3) D<0
(-4)² -4(m)(m) < 0
16 - 4m² <0
m²> 4
m < -2 atau m > 2
4. (sin a + cos b)² = p²
1 + 2 sin a cos b = p²
2 sin a cos b = p² -1
sin a - cos b = +_√( sin a - cos b)² = +-√(1 - 2 sin a cos b)
= +-√(1 - (p²-1))
= +-√(2-p²)
5)
a = ( 2²⁰¹⁷ - 2²⁰¹⁶)/ (2²⁰¹⁵ - 2²⁰¹⁴)
a = 2²⁰¹⁶ (2 - 1) / 2² ⁰¹⁴ (2 -1)
a= 2² = aˣ
a= 2 , x = 2
a- x = 0
7. 3x² + ax - 2 = 0 ,akar saling berkebalikan dengan 2x² + 6x + 3b
maka
a= 6
3 = 3b --> b = 1
b - a = 1 - 6 = - 5
8.
f(x) = √(x²+1)
y² = x² + 1
x² = y²-1
x = √(y²-1)
f⁻¹(x)= √(x² -1)
fog(x) = 1/(x-2) √(x² - 4x +5)
g(x) = f⁻¹ { fog(x)}
g(x) = √ [(x²-4x+5)/(x-2)² - 1 ]
g(x) = √ [ (x² -4x + 5 - (x-2)²)/(x-2)²]
g(x) = 1/(x-2) √(x²-4x + 5 - x²+4x - 4)
g(x) = 1/(x-2 ) √(1)
g(x) = 1/(x-2)
g(x -3) = 1/ (x - 3 - 2) = 1/(x - 5)