tolong jawab no 6 dan 7 ya mkshh!!!:))

Soal No. 6

[tex] \frac{x^2-4x}{x^2-2x-8} = \frac{x(x-4)}{(x-4)(x+2)}= \frac{x}{x+2} [/tex]

Jawaban (A)

Soal No. 7

[tex] \frac{2}{3} x+2= \frac{1}{4}x+3 \\ \\ \frac{2}{3} x- \frac{1}{4}x=3-2 \\ \\ \frac{8-3}{12}x=1 \\ \\ \frac{5}{12}x =1 \\ \\ x=1 \times \frac{12}{5} \\ \\ x=2,4 [/tex]

x + 3 = 2,4 + 3 = 5,4 .................Jawaban (D)