Matematika

Pertanyaan

Lim x-0 cos 8x -1/x sin 4x

2 Jawaban

  • cos 8x = cos(4x+4x) = cos4x cos4x - sin4 sin4x = cos^2 4x - sin^2 4x
    Gambar lampiran jawaban yuda23
  • jawab

    limit (x->0) ( cos 8x - 1) / ( x. sin 4x)

    lim(x->0)  (1 - 2 sin² 4x - 1) / (x sin 4x)

    lim(x->0)  ( - 2 sin² 4x) / (x sin 4x)

    = - 2 (4)²/ (1)(4)
    = -8

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