tentukan harga x jika diketahui akar2^x+2=(1/8)^1-x plis dibantu yak

jawav

√(2)ˣ⁺² = ( 1/8)¹⁻ˣ

(2)⁽ˣ⁺²⁾/²  = (2⁻³)¹⁻ˣ

(x + 2) /2 = -3(1- x)

(x + 2) = -6 (1- x)

x + 2 = -6 + 6x

x - 6x = - 6 - 2

- 5x = -8

x =  8/5