[tex] \sqrt{3+2 \sqrt{2} } - \sqrt{2} =

[tex] \sqrt{(a+b) + 2 \sqrt{a.b} } = \sqrt{a} + \sqrt{b} [/tex]

[tex]\sqrt{3+2 \sqrt{2} } - \sqrt{2} = \sqrt{(2 + 1)+2 \sqrt{2.1} } - \sqrt{2} = \sqrt{2} + \sqrt{1} - \sqrt{2} = \sqrt{1} = 1 [/tex]

Jawabannya:
√3+2√2-√2
=√2+1+2√2×1-√2
=√2+√1-√2
=√3-√2
=√1
= 1

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