Tolong bantu pake caranya

(3x-4y) (4x+3y)
pertama 3x×4x=12x^2
lalu (3x×3y)+(-4y×4x)= (9xy)+(-16xy)= (-7xy)
terakhir -4y×3y= -12y^2

jadi jawabannya 12x^2-7xy-12y^2 (A)

Jawab:
[tex](3x - 4y)(4x + 3y) \\ = (3x \times 4x) + (3x \times 3y) + ( - 4y \times 4x) + ( - 4y \times 3y) \\ = (12x ^{2} ) + (9xy) + ( - 16xy) + ( - 12y ^{2} \\ = 12 {x}^{2} - 12 {y}^{2} - 7xy[/tex]
atau ditulis
[tex]12 {x}^{2} - 7xy - 12 {y}^{2} [/tex]
Jawaban A