Matematika

Pertanyaan

mohon dibantu dg cara ya
mohon dibantu dg cara ya

1 Jawaban

  • a) 3/√2
    = 3/√2  x √2/√2
    = 3√2/2

    b) √(3/5)
    = √3/√5 x √5/√5
    = √15/5

    c) -6/√7
    = -6/√7 x √7/√7
    = -6√7/7

    d) 3-√6/3+√6
    = 3-√6/3+√6 x 3-√6/3-√6
    = 9 - 3√6 - 3√6 + 6 / 9 - 3√6 + 3√6 - 6
    = 15 - 6√6 / 3
    = 5 - 2√6

    e) 1/√3+√7
    = 1/√3+√7 x √3-√7/√3-√7
    = √3-√7/ 3 - √21 + √21 - 7
    = √3-√7/-4