mohon dibantu dg cara ya
Matematika
lala1251
Pertanyaan
mohon dibantu dg cara ya
1 Jawaban
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1. Jawaban sitiamirah0505
a) 3/√2
= 3/√2 x √2/√2
= 3√2/2
b) √(3/5)
= √3/√5 x √5/√5
= √15/5
c) -6/√7
= -6/√7 x √7/√7
= -6√7/7
d) 3-√6/3+√6
= 3-√6/3+√6 x 3-√6/3-√6
= 9 - 3√6 - 3√6 + 6 / 9 - 3√6 + 3√6 - 6
= 15 - 6√6 / 3
= 5 - 2√6
e) 1/√3+√7
= 1/√3+√7 x √3-√7/√3-√7
= √3-√7/ 3 - √21 + √21 - 7
= √3-√7/-4