Persamaan grafik fungsi kuadrat yang puncaknya (-2,6) dan melalui titik (0,4)

Kelas 10 Matematika
Bab Fungsi Kuadrat

y - yp = a (x - xp)²
4 - 6 = a . (0 + 2)²
-2 = a . 4
a = -2/4
a = -1/2

y = a (x - xp)² + yp
y = (-1/2) . (x + 2)² + 6
y = (-1/2) . (x² + 4x + 4) + 6
y = (-1/2) x² - 2x - 2 + 6
y = (-1/2) x² - 2x + 4

Jawabannya:

Xpuncak→ -b/2a
-b/2a= -2
-b= -4a
b= 4a

f(x)= ax²+bx+c
f(x)= ax²+4ax+c

f(0)= 4
a(0)²+4a(0)+c=4
c=4

f(x)= ax²+4ax+4
f(-2)=6
a(-2)²+4a(-2)+4=6
4a-8a+4=6
-4a=6-4
-4a= 2
a= 2/-4
a= -1/2

f(x)= ax²+4ax+4
f(x)= -1/2x²-2x+4

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