Matematika

Pertanyaan

tolong tolong tolong tolong no. 22 & 24 ajaaaaa kls 6666
tolong tolong tolong tolong no. 22 & 24 ajaaaaa kls 6666

2 Jawaban

  • 22
    Keliling lingkaran
    K = 2 x pi x r
    K = 2 x 3,14 x 25 cm
    K = 157 cm

    Jawabannya B

    24
    Luas lingkaran
    L = pi x r x r
    L = 3,14 x 10 cm x 10 cm
    L = 314 cm²

    Jawabannya B
  • 22.
    [tex]2\pi \times r \\ 2 \times 3.14 \times 25 \\ 6.28 \times 25 \\ 157[/tex]
    jawaban = b

    23.
    [tex] \frac{1}{2} a \times t \\ \frac{1}{2} 36 \times 20 \\ 36 \times 10 \\ 360[/tex]
    jawaban =c

    24.
    [tex]\pi \times r {}^{2} \\ 3.14 \times 10 \times 10 \\ 314[/tex]
    jawaban = b