4log1/32 + 3log243 - 2 125 log 625=?

Kelas 10 Matematika
Bab Logaritma

^ = pangkat

^4log (1/32) + ^3log 243 - 2 . ^125log 625
= ^(2²)log 2^(-5) + ^3log 3^5 - 2 . ^(5^3)log 5^4
= (-5/2) . ²log 2 + 5 . ^3log 3 - 2 . (4/3) . ^5log 5
= -5/2 + 5 - 8/3
= -15/6 + 30/6 - 16/6
= -1/6