(81)^1/2+(27)^2/3-2^3

[tex]=81^ \frac{1}{2}+ 27^ \frac{2}{3} - 2^3 \\ \\ = (9^2)^ \frac{1}{2}+(3^3)^ \frac{2}{3}-2^3 \\ \\ =9^{(2 \times \frac{1}{2})}+3^{(3 \times \frac{2}{3})}-2^3 \\ \\ =9+3^2-2^3 \\ \\ =9+9-8 \\ \\ =10 [/tex]

Jawabannya;

(81)^½ + (27)^⅔ - 2³
= 9²^1/2+ 3³^2/3 - 8
= 9^2×1/2+3^3×2/3 - 8
= 9+3²-8
= 9+9-8
= 18-8
= 10

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