Matematika

Pertanyaan

Ada yang bisa bantu No 3?
Ada yang bisa bantu No 3?

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1 Jawaban

  • a
    = ( 3 + 2 × (2)^1/2 )^1/2
    = 1^1/2 + 2^1/2

    b
    = ( 6 + 2 × (8)^1/2 )^1/2
    = 2^1/2 + 4^1/2

    a^2 + b^2 - 2ab
    = (a - b)^2
    = [(1^1/2 + 2^1/2) - (2^1/2 + 4^1/2)]^2
    = (1^1/2 + 2^1/2 - 2^1/2 - 4^1/2)^2
    = (1^1/2 - 4^1/2)^2
    = (1 - 2)^2
    = (-1)^2
    = 1 (a)

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