[tex] \sqrt{2 ^{x + 3} } = (\frac{1}{4} )^{x + 4} [/tex] Maka x adalah... .

[tex] \sqrt{ {2}^{x + 3} } = (\frac{1}{4}) {}^{x + 4} \\ {2}^{ \frac{x + 3}{2} } = {2}^{ - 2(x + 4)} \\ \frac{x + 3}{2} = - 2x - 8 \\ x + 3 = - 4x - 16 \\ x + 4x = - 3 - 16 \\ 5x = - 19 \\ x = \frac{ - 19}{5} [/tex]
emang pecahan jawabannya, udah aku coba pakai photomath