mohon dijawab plis mohon cepatt trimakasih

[tex] \sqrt{7 {}^{2m + 4} } = 49 {}^{m - 2} \\ 7 {}^{ \frac{1}{2} (2m + 4)} = 7 {}^{2(m - 2)} \\ \frac{1}{2} (2m + 4) = 2(m - 2) \\ m + 2 = 2m - 4 \\ m - 2m = - 4 - 2 \\ - m = - 6 \\ m = 6[/tex]

Jadi, jawabannya D.