Matematika

Pertanyaan

tolong sih jwb + cara lnkap.... plesss
-1 < 3^log (2x-1) contohnya kyak gni tinggal diubah tp ak gk bsa..

-1<2^log (x-2)
=2^log2 ^-1 < 2^log (x-2) ......^-1 nya diatas 2
=1/2 < x-2
=2 ½ < x.....

1 Jawaban

  • [tex]-1<^3\log(2x-1) \\ ^3\log(2x-1)>-1 \\ ^3\log(2x-1)>^3\log3^{-1} \\ ^3\log(2x-1)>^3\log\frac{1}{3} \\ 2x-1>\frac{1}{3} \\ 2x>1+\frac{1}{3} \\ 2x>\frac{4}{3} \\ x>\frac{2}{3}[/tex]

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