Apa ada yg bisa bantu gimana cara ngerjain ini?

J (x +2)(x + a) dx = 3a + 4 untuk x dari 0 sampai 1
= J (x^2 + ax + 2x + 2a ) dx
= J (x^2+ (a +2)x +2a) dx
= (1/3)x^3 + (a+2)x^2/2 + 2ax , batas 0 sampai 1
={ (1/3).1^3 + (a+2).1^2/2 +2a.1 } - (0) = 3a +4
=>1/3 + (a+2)/2 + 2a = 3a + 4 . (kali 6)
=>( 2 + 3a + 6 + 12a = 18a + 24)
=>3a + 12a -18a = 24 -8
=> -3a = 16
=> a = -16/3
b) a^2 -2a +1
(a -1)^2
= (-16/3 -1)^2
= (-19/3)^
= .....