solusi persamaan (ada difoto)

[tex] \frac{8}{( 2^{3-4} )^{2}} = \sqrt[3]{ \frac{1}{16} } [/tex]
=> [tex] \frac{ 2^{3} }{(2^{-1})^2} = \sqrt[3]{ \frac{1}{2^{4}} }[/tex]
=> [tex] \frac{2^{3}}{2^{-2}} = \sqrt[3]{ 2^{-4} }[/tex]
=> [tex]2^{3-(-2)} = 2^{- \frac{4}{3}}[/tex]
=> [tex]\frac{2^{3+2}}{2^{- \frac{4}{3}}}[/tex]
=> [tex] 2^{5 + \frac{4}{3}} [/tex]
=> [tex] 2^{\frac{19}{3}} [/tex]