1.fx)=5x (x-4)2 2.f(x)=(x-6) (x+2)2 3.f(x)=(x+3) (x+1) (x-5) 4.f(x)=(2x+1) (3x+2)2 5.f(x)=(3x-7) (2x-3)2 tentukan derajat polinomnya
Matematika
donq
Pertanyaan
1.fx)=5x (x-4)2
2.f(x)=(x-6) (x+2)2
3.f(x)=(x+3) (x+1) (x-5)
4.f(x)=(2x+1) (3x+2)2
5.f(x)=(3x-7) (2x-3)2
tentukan derajat polinomnya
2.f(x)=(x-6) (x+2)2
3.f(x)=(x+3) (x+1) (x-5)
4.f(x)=(2x+1) (3x+2)2
5.f(x)=(3x-7) (2x-3)2
tentukan derajat polinomnya
1 Jawaban
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1. Jawaban ulyrosari
1. f (x) = 5x ( 2x -8) = 10x² - 40 x. derajat polinom = 2
2. f(x)= x-6 ( 2x+4) = 2x²+4x-12x -24 = 2x² - 8x -24. jadi jwab 2
3. f(x) = (x² +x+3x+3)(x-5) = x³-5x²+x²-5x+3x²-15x +3x-15 = x³-x²-17x-15. polinom = 3
4. f(x) = ( 2x+1) ( 6x+4) = (12x²+8x+6x+4) = 12x²+14x+4. polonom = 2
5. f(x) = 3x-7 (4x-6) = 12x²-18x-28x+42 = 12x²-38x+42. polinom = 2