nilai dari 2 log 25 dikali 3 log 8 dikali 5 log 9 adalah

Jawabannya:

²log25 × ³log8 × ^5log9
= ²log5² × ³log2³ × ^5log3²
= 2×3×2
= 6×2
= 12

# Maaf Kalo Salah

[tex] {}^{2} log25 \times {}^{3} log8 \times {}^{5} log9 \\ = {}^{2} log {5}^{2} \times {}^{3} log {2}^{3} \times {}^{5} log {3}^{2} \\ = {2}^{2} log5 \times {3}^{3} log2 \times {2}^{5} log3 \\ = 2 \times 3 \times 2 \times {}^{2} log5 \times {}^{5} log3 \times {}^{3} log2 \\ = 12 \times {}^{2} log3 \times {}^{3} log2 \\ = 12 \times {}^{2} log2 \\ = 12[/tex]