Persamaan grafik fungsi kuadrat yang puncaknya (-2,6) dan melalui titik (0,4)

(x,y) =(0,4)
(xp,yp) = (-2,6)

y = a(x - xp)² + yp
4 = a(0-(-2))² + 6
4 = 4a + 6
4a = -2
a = -1/2

y = -1/2 (x - (-2))² + 6
y = -1/2 (x + 2)² + 6
y = -½ (x² + 4x + 4) + 6
y = -½x² - 2x - 2 + 6
y = -½x² -2x + 4

Jawabannya:

Xpuncak→ -b/2a
b/2a= -2
-b= -4a
b= 4a

f(x)= ax²+bx+c
f(x)= ax²+4ax+c

f(0)=4
a(0)²+4a(0)+c=4
c=4

f(x)= ax²+4ax+4
f(-2)=6
a(-2)²+4a(-2)+4=6
4a-8a+4=6
-4a= 6-4
-4a=2
a= 2/-4
a= -1/2

f(x)= ax²+4ax+4
f(x)= -1/2x²-2x+4

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