Tolong bantu nomer 7 dan 8 ya,,

7. [H+] = √​ka​​​×ma
= √​1.8​​​ × 10​−4 ​​× 0.05
= √​1.8 ​​​× 10​−4​​ ×5 × 10​−2​​
= √​9​​​×10​−6​​
= 3 x 10-3
8. pH = -log [H+]
5 = -log [H+]
[H+] = 10-5
[H+] = α x Ma
10-5 = α x 0,01
α = 10​−5​​​​ / 10-2
α =10-3 = 0,001