Akar 6 log 8 di kali 16 log 36

[tex] ^{6} log_{8} \times {}^{16} log_{36} = ... \\ = {}^{6} log( {2}^{3} ) . {}^{ {2}^{4} } log( {6}^{2} ) \\ = 3. {}^{6 } log(2). \frac{1}{4} {}^{2} log( {6}^{2} ) \\ \\ = \frac{3}{4} \times {}^{6} log(2) . {}^{2} log( {6}^{2} ) \\ \\ = \frac{3}{4} \times {}^{6} log( {6}^{2} ) \\ \\ = \frac{3}{4} \times 2 \\ \\ = \frac{3}{2} \\ rumus \: \\ ^{ {a}^{n} } log(x) = \frac{1}{n} {}^{a} log(x) \\ \\ {}^{a} log(b) . {}^{b} log(c) = {}^{a} log(c) \\ \\ {}^{a} log{ {x}^{p} } = p. {}^{a} log(x) [/tex]

Jadi, untuk akar 6 log 8 × 16 log 36 = √(3/2)