mohon bantuannya yayayay???

Kelas : X SMA
Mapel : Matematika Peminatan
Bab : Fungsi Eksponensial dan Logaritma
Indikator : Persamaan Eksponensial

Langkah Penyelesaian dan Jawaban :

[tex]3^{2x+1} + 27 = 82\cdot3^x \\\\ (3^x)^2 \cdot 3 + 27 = 82\cdot3^x \\\\ mis \ 3^x = p \\\\ p^2\cdot 3 + 27 = 82p \\\\ 3p^2 - 82p + 27 = 0 \\\\ (3p - 1)(p - 27) = 0 \\\\ p = \frac{1}{3} \ atau \ p = 27 \\\\ 3^x = \frac{1}{3} \ atau \ 3^x = 27 \\\\ 3^x = \frac{1}{3}\\ 3^x = 3^{-1} \\ x = - 1 \\\\ 3^x = 27\\ 3^x = 3^3 \\ x = 3 \\\\ HP = {- 1, 3} [/tex]