Kak tolong di batu nomor 2(c,d,f)

rumus teorama pythagoras
jika
a : sisi berdiri
b : sisi bawah
c : sisi miring
[tex] \sqrt{ {a}^{2} + {b}^{2} } = c[/tex]

c.)
[tex] = \sqrt{ {10.6}^{2} - {5.6}^{2} } \\ = \sqrt{112.36 - 31.36} \\ = \sqrt{81} \\ = 9[/tex]

d.)
[tex] = \sqrt{ {10.4}^{2} - {9.6}^{2} } \\ = \sqrt{108.16 - 92.16} \\ = \sqrt{13} \\ = 4[/tex]

f.)
[tex] = \sqrt{ {9.6}^{2} + {7.2}^{2} } \\ = \sqrt{92.16 + 51.84} \\ = \sqrt{144} \\ = 12[/tex]

semoga membantu :)